a.ta có :4^2.4^3/2^10=2^4.2^6/2^10=2^10/2^10=1

b. ta co :(0,6)^5/(0,2)^5=(0,6/0,2)^5=3^5=243

a) \(-\frac{8}{18}-\frac{15}{27}\)

\(=-\frac{4}{9}-\frac{5}{9}\)

\(=-\frac{9}{9}=-1\)

b) \(\frac{1}{2}\cdot\sqrt{100-\sqrt{\frac{1}{16}+\left(\frac{1}{3}\right)^0}}\)

\(=\frac{1}{2}\cdot\sqrt{100-\sqrt{\frac{1}{16}+1}}\)

\(=\frac{1}{2}\sqrt{100-\sqrt{\frac{17}{16}}}\)

Cái này ra số thập phân dài lắm

c) \(\frac{5^4\cdot20^4}{25^5\cdot4^5}=\frac{5^4\cdot5^4\cdot4^4}{5^5\cdot5^5\cdot4^5}=\frac{1}{100}\)

a) \(\frac{-8}{18}-\frac{15}{27}\)

\(=\frac{-4}{9}-\frac{5}{9}\)

\(=\frac{-9}{9}\)

\(=-1\)

b) \(\frac{1}{2}\sqrt{100-\sqrt{\frac{1}{16}+\left(\frac{1}{3}\right)^0}}\)

\(=\frac{1}{2}\sqrt{100-\sqrt{\frac{1}{16}+1}}\)

\(=\frac{1}{2}\sqrt{100-\sqrt{\frac{17}{16}}}\)

\(=\sqrt{\frac{1}{4}.100-\frac{1}{4}\sqrt{\frac{17}{16}}}\)

\(=\sqrt{25-\frac{\sqrt{17}}{16}}\)

c) \(\frac{5^4.20^4}{25^5.4^5}\)

\(=\frac{5^4.2^8.5^4}{5^{10}.2^{10}}\)

\(=\frac{5^8.2^8}{2^{10}.5^{10}}\)

\(=\frac{10^8}{10^{10}}\)

\(=\frac{1}{10^2}\)

\(=\frac{1}{100}\)

a) \(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.\left(5.2^2\right)^4}{\left(5^2\right)^5.\left(2^2\right)^5}=\frac{5^4.5^4.2^8}{5^{10}.2^{10}}=\frac{5^8.2^8}{5^{10}.2^{10}}=\frac{1}{5^2.2^2}=\frac{1}{25.4}=\frac{1}{100}.\)

Chúc bạn học tốt!

no l can't help you

Bài làm

\(a,\left(\frac{3}{7}+\frac{1}{2}\right)^2\)

\(=\left(\frac{3}{7}\right)^2+\left(\frac{1}{2}\right)^2\)

\(=\frac{9}{49}+\frac{1}{4}\)

\(=\frac{36}{196}+\frac{49}{196}\)

\(=\frac{85}{196}\)

\(b,\left(\frac{3}{4}-\frac{5}{6}\right)^2\)

\(=\left(-\frac{1}{12}\right)^2\)

\(=\frac{1}{144}\)

\(c,\frac{5^4.20^4}{25^5.4^5}\)

\(=\frac{5^4.\left(5.4\right)^4}{\left(5.5\right)^5.4^5}\)

\(=\frac{5^4.5^4.4^4}{5^5.5^5.4^5}\)

\(=\frac{1}{5.5.4}\)

\(=\frac{1}{100}\)

~ Check đúng cho minh nha. ~

# Học tốt #

\(a,\left(\frac{3}{7}+\frac{1}{2}\right)^2\)

\(< =>\left(\frac{6}{14}+\frac{7}{14}\right)^2\)

\(< =>\left(\frac{13}{14}\right)^2\)

\(< =>\frac{169}{196}\)

\(b,\left(\frac{3}{4}-\frac{5}{6}\right)^2\)

\(< =>\left(\frac{9}{12}-\frac{10}{12}\right)^2\)

\(< =>\left(\frac{-1}{12}\right)^2\)

\(< =>\frac{-1}{144}\)

\(c,\frac{5^4\cdot20^4}{25^5\cdot4^5}\)

\(< =>\frac{25^2\cdot\left(4\right)^4\cdot\left(5\right)^4}{25^5\cdot4^5}\)

\(< =>\frac{1\cdot1\cdot\left(5\right)^4}{25^3\cdot4}\)

\(< =>\frac{1\cdot25^2}{25^3\cdot4}\)

\(< =>\frac{1}{25\cdot4}\)

\(< =>\frac{1}{100}\)

1: \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^6\)

\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{4x}=\left(\dfrac{1}{2}\right)^{18}\)

=>4x=18

hay x=9/2

2: \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^{36}\)

\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{4x}=\left(\dfrac{1}{2}\right)^{108}\)

=>4x=108

hay x=27

3: \(\left(\dfrac{1}{81}\right)^x=\left(\dfrac{1}{27}\right)^4\)

\(\Leftrightarrow\left(\dfrac{1}{3}\right)^{4x}=\left(\dfrac{1}{3}\right)^{12}\)

=>4x=12

hay x=3

làm cho 1 cái những cái sau tương tự mà lm nha bạn

\(\frac{x}{5}=-\frac{6}{7}\)

\(=>7x=-6\cdot5\)

\(7x=-30\)

\(x=-\frac{30}{7}\)

\(\frac{x}{2}=-\frac{8}{-x}\)

\(=>\frac{x}{2}=\frac{8}{x}\)

\(=>xx=8\cdot2\)

\(x^2=16\)

\(=>x\in\left\{-4;4\right\}\)